Trận đấu
Đội hình Den Bosch vs Jong Ajax, 11/02/2023
Đội hình ra sân
Den Bosch HLV: de Gier J.
4-2-3-1
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1. van der Steen
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18. Mulders
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15. van Grunsven
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23. Bowat
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45. Gyamfi
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7. Ahannach
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8. van der Heijden
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11. Verbeek
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22. Hammouti
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17. Kalinauskas
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10. Konings
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9. Lucca
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11. Martha
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10. Hlynsson
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7. Rasmussen
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8. Fitz-Jim
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6. Cliff Robbie Vos
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5. Hato
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4. Warmerdam
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3. Aertssen
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2. Regeer
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1. de Graaff
Jong Ajax HLV: Kreek M.
4-2-3-1
Dự bị
25
![Barglan](https://mediares.thethao247.vn/res/image/data/GAW2hMwS-xjn6FR0F.png)
Barglan
42
![Patoulidis](https://mediares.thethao247.vn/res/image/data/YNStibjl-8SchSWEh.png)
Patoulidis
4
![Ryan](https://mediares.thethao247.vn/res/image/data/jo2pepCa-AJr9NvFP.png)
Ryan
21
![Sikking](https://mediares.thethao247.vn/res/image/data/UBiIhgYg-v99XbDJh.png)
Sikking
19
![van Bakel](https://mediares.thethao247.vn/res/image/data/vJd1YIYg-d00f8iSJ.png)
van Bakel
3
![van den Bogert](https://mediares.thethao247.vn/res/image/data/lttRETg5-IsaF1ch6.png)
van den Bogert
39
![van Hees](https://mediares.thethao247.vn/res/image/data/Iu6N9odM-WpeJOsyS.png)
van Hees
31
![Vrolijks](https://mediares.thethao247.vn/res/image/data/EgUHvrCa-tWhDSOsc.png)
Vrolijks
6
![Zelalem](https://mediares.thethao247.vn/res/image/data/YcoAPwvS-2HNl8BjP.png)
Zelalem
15
![Banel](https://mediares.thethao247.vn/res/image/data/IVUp0dyS-YiONZidF.png)
Banel
17
![Gooijer](https://mediares.thethao247.vn/res/image/data/Ct0oOdZA-zZDdCVOn.png)
Gooijer
16
![Hansen](https://mediares.thethao247.vn/res/image/data/Eoz9HcYg-hfIlBDf6.png)
Hansen
19
![Misehouy](https://mediares.thethao247.vn/res/image/data/Is3DFjg5-YiONZidF.png)
Misehouy
12
![Setford](https://mediares.thethao247.vn/res/image/data/rkAI3IBr-IqtLnkP2.png)
Setford
18
![van Axel Dongen](https://mediares.thethao247.vn/res/image/data/URsVX5yS-MugwO5n2.png)
van Axel Dongen
Huấn luyện viên
![de Gier J.](http://www.bangdainfo.com/livescores/templates/themes/images/no-photo/no-avatar.png)
de Gier J.
![Kreek M.](http://www.bangdainfo.com/livescores/templates/themes/images/no-photo/no-avatar.png)
Kreek M.